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If the conventional current of the wire is 8 amperes, what is the magnetic field at the center of the coil?

a. 2 Tesla
b. 4 Tesla
c. 8 Tesla
d. 16 Tesla

User Brian Kim
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1 Answer

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Final Answer:

The magnetic field at the center of the coil is 4 Tesla (b).

Step-by-step explanation:

The magnetic field at the center of a coil can be determined using the formula B = (μ₀ * n * I) / (2 * R), where B is the magnetic field strength, μ₀ is the permeability of free space (4π × 10^(-7) T m/A), n is the number of turns per unit length, I is the current, and R is the radius of the coil.

In this case, the conventional current (I) is given as 8 amperes. Assuming a single-loop coil, the number of turns per unit length (n) is essentially 1. The formula simplifies to B = (4π × 10^(-7) T m/A) * (1) * (8 A) / (2 * R).

Now, let’s consider the multiple-choice options and evaluate the result. If we choose option (b) 4 Tesla, the formula becomes B = (4π × 10^(-7) T m/A) * (1) * (8 A) / (2 * R) = (2 * π × 10^(-7) T m/A) * (8 A) / R.

As we can see, the radius (R) cancels out, leaving us with a magnetic field strength of 4π × 10^(-7) T. Numerically, this is approximately 4 Tesla. Therefore, the correct answer is 4 Tesla, aligning with option (b).

User Bbrinck
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