Question

A sample of a solution for injection is found to contain 1.4 ppm of lead chloride. How much of the solution (in ml) will contain 50 micrograms of lead chloride?

a) Applying dilution calculations in pharmaceutical solutions.
b) Interpreting parts per million (ppm) concentration.
c) Calculating the volume of a solution containing a specific compound.
d) Analyzing the dosage requirements in pharmaceutical formulations.

Answer 1

To determine how many milliliters of a 1.4 ppm lead chloride solution would contain 50 micrograms of lead chloride, use the proportion 1.4 µg/mL = 50 µg/X mL, resulting in approximately 35.71 mL of the solution.

Step-by-step explanation:

The question involves interpreting parts per million (ppm) concentrations as well as calculating the volume of a solution containing a specific amount of a compound, which in this case is lead chloride. To solve this, we will need to apply the concept of concentration to calculate how much volume contains a particular mass of solute.

Given that the concentration of lead chloride is 1.4 ppm, this means there are 1.4 micrograms of lead chloride per milliliter of solution. To find out how much volume (in milliliters) would contain 50 micrograms of lead chloride, we can set up a simple proportion:

1.4 µg/mL = 50 µg/X mL

To solve for X, which represents the volume in milliliters, we cross-multiply and divide:

X = (50 µg × 1 mL) / 1.4 µg

X ≈ 35.71 mL

Therefore, approximately 35.71 mL of the solution would contain 50 micrograms of lead chloride.