We are given two solutions of C12H22O11, where solution 1 is 20% and solution 2 is 60%.
We want to know how much of each solution we need to get 38% in 50 mL of C12H22O11.
We can use the following equation:
C1V1 = C2V2
For a 20% concentration:
V1 = C2V2/C1
= (38% x 50mL)/20%
= 95mL
For a 60% concentration:
V1 = C2V2/C1
= (38% x 50mL)/60%
= 31.6mL
So to get a 50mL of 38%, you can use the 20% solution provided, you will need to use 95 mL of 20% concentration to get 38% final concentration. And if you use the 60% concentration solution provided, you will need to use 31.6mL.