Final answer:
The ionization reaction of sodium chloride in water is NaCl(s) → Na+ (aq) + Cl− (aq), where NaCl dissociates into sodium and chloride ions in an aqueous solution.
Step-by-step explanation:
The ionization reaction for sodium chloride (NaCl) when dissolved in water to form an aqueous solution is represented as follows:
NaCl(s) → Na+ (aq) + Cl− (aq)
This process is referred to as dissociation, where the sodium and chloride ions separate and become solvated by water molecules. Each ion is indicated with its respective charge (Na+ for sodium ion and Cl− for chloride ion), and the (aq) indicates that they are in the aqueous phase, meaning they are dissolved in water.