9.8k views
4 votes
Determine the shortest wavelength of light required to remove a single electron from a sample of titanium metal.

a) y=mx+c
b) E=mc^2
c) E=hf
d) PV=nRT

User Nawaz
by
8.0k points

1 Answer

1 vote

Final answer:

The shortest wavelength of light required to remove a single electron from a sample of titanium metal depends on the work function of titanium, which is not provided. However, shorter wavelengths of light have higher frequencies and energy, increasing the likelihood of electron ejection.

Step-by-step explanation:

The shortest wavelength of light required to remove a single electron from a sample of titanium metal can be determined using the formula E=hf, where E is the energy of the photon, h is Planck's constant (4.14 x 10-15 eV s), and f is the frequency of the light wave. The relationship between wavelength and frequency is given by c = λf, where c is the speed of light (2.998 x 108 m/s) and λ is the wavelength of the light wave. By rearranging this equation, we can solve for the wavelength (λ = c/f). The energy required to remove a single electron from titanium is known as the work function (W0).

Given that the work function of titanium is not provided, it is not possible to determine the exact minimum wavelength required to remove a single electron from the metal. The work function value is specific to each material and can vary. However, the general concept is that the shorter the wavelength of light, the higher the frequency and energy of the photons, which increases the likelihood of electron ejection.

To summarize, the shortest wavelength of light required to remove a single electron from a sample of titanium metal depends on the work function of titanium, which is not provided. However, shorter wavelengths of light have higher frequencies and energy, increasing the likelihood of electron ejection.

User Debabrata
by
6.3k points