Question

Convert 0.200 g of sodium carbonate and 0.200 g of sodium bicarbonate to moles. Molar mass of sodium carbonate:

a) Na2CO3: 105.99 g/mol
b) NaHCO3: 84.01 g/mol
c) Na2CO3: 106.0 g/mol
d) NaHCO3: 84.0 g/mol

Answer 1

To convert grams to moles for sodium carbonate and sodium bicarbonate, divide the given mass by their molar masses, resulting in 0.001887 moles for sodium carbonate and 0.002381 moles for sodium bicarbonate.

Step-by-step explanation:

To convert 0.200 g of sodium carbonate to moles, use the molar mass from the given options. Assuming molar mass option (c) is correct, the calculation would be:

0.200 g Na2CO3 ÷ 106.0 g/mol = 0.001887 moles Na2CO3

For 0.200 g of sodium bicarbonate, using molar mass option (d):

0.200 g NaHCO3 ÷ 84.0 g/mol = 0.002381 moles NaHCO3

The calculations are based on the molar masses of the compounds, where one mole is equivalent to the mass of 6.02 × 1023 representative particles.

Answer 2

0.00189 (or 1.89*10^-3) moles of sodium carbonate and 0.0024 (or 2.4*10^-3) moles of sodium bicarbonate

Step-by-step explanation:

So we have 0.200g of Na₂CO₃ and 0.200g of NaHCO₃.

If we have 0.200g of Na₂CO₃ and the molar mass is 105.99g/mol (or 106g/mol if we round it up):

0.200g* 1 mol/105.99g= 0.00189 moles of Na₂CO₃ (which is 1.89*10^-3 moles of Na₂CO₃)

Basically what I did here was simply using conversion factors, 1 mol=105.99g we have grams and want moles so we put the grams as the denominator to get rid of them

If we have 0.200g of NaHCO₃ and the molar mass is 84.01g/mol (or 84g/mol):

0.200g*1mol/84.01g =0,0024 moles of NaHCO₃ (which is 2.4*10^-3 moles of NaHCO₃)

(I don't know if they're asking you for the full number which I think they're not but just in case here you go:

0,00188679245283018867924528301887

0,00238095238095238095238095238095)