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Three real numbers are chosen from the interval. What is the probability that the largest number is between 3 and 4?

a) (1/3)
b) (1/4)
c) (1/2)
d) (1/6)

User Fliim
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1 Answer

4 votes

Final answer:

To find the probability that the largest number is between 3 and 4 when choosing three real numbers, we need to consider the interval and calculate the probability based on that. Without specific values for the interval, we can't provide a numerical answer.

Step-by-step explanation:

To find the probability that the largest number is between 3 and 4, we need to first consider the total number of possibilities for choosing three real numbers from the interval. Let's assume the interval is [a, b].

If the largest number is between 3 and 4, then the other two numbers can be any real numbers from the interval [a, 3] and [4, b].

So, the probability of the largest number being between 3 and 4 is the same as the probability of choosing two real numbers from the interval [a, 3] and [4, b].

Since the probability of choosing a real number from the interval [a, 3] is (3-a)/(b-a) and the probability of choosing a real number from the interval [4, b] is (b-4)/(b-a), the probability of the largest number being between 3 and 4 is ((3-a)/(b-a))*((b-4)/(b-a)) = (3-a)(b-4)/(b-a)^2.

To determine the exact value of the probability, we need the specific values of a and b from the interval. Without that information, we can't provide a numerical answer.

User Hellzone
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