Final answer:
To find the probability of drawing two consecutive red marbles, multiply the probability of drawing a red marble on the first draw (4/9) by the probability of drawing another red marble on the second draw (3/8), giving you 1/6.
Step-by-step explanation:
The question is asking for the probability of drawing two consecutive red marbles from a bag containing 4 red, 3 blue, and 2 white marbles. Since there are a total of 9 marbles, the chance of picking one red marble on the first draw is 4 out of 9 (4/9). After one red marble is taken, there are 3 red marbles left and the total count of marbles is reduced to 8. Therefore, the probability for the second draw is 3 out of 8 (3/8). To find the combined probability of both events happening one after the other, we multiply the probabilities of each individual event: (4/9) Ă— (3/8) = 12/72, which simplifies to 1/6. Thus, the correct answer is c) 1/6.