Final answer:
The matrix (B^-1AB) has the same eigenvalues as (A) and the eigenvectors are orthogonal.
Step-by-step explanation:
To show that (B-1AB) has the same eigenvalues as (A), we can use the property that similar matrices have the same eigenvalues. Since (B-1AB) is similar to (A), they will have the same eigenvalues.
The relationship between the eigenvectors of (A) and (B-1AB) depends on the transformation that matrix B-1 represents. If B-1 is an orthogonal matrix, then the eigenvectors will be orthogonal to each other. Therefore, the correct answer is a) They are orthogonal.