Final answer:
The mass and heat transfer of helium in a closed, rigid container undergoing a constant volume heating process can be determined using the ideal gas law and the concept of internal energy change. The mass is calculated from initial conditions using the equation PV= mRT, and the heat transfer is determined based on the change in internal energy, ΔU, which equals the heat transfer (Q) in a constant volume process. Option D correctly describes the relationship between temperature and pressure changes in this scenario.
Step-by-step explanation:
The question relates to a closed system containing helium, which is considered as an ideal gas and is undergoing a constant volume heating process. To find the mass of the helium, we use the ideal gas equation PV = mRT, where P is the pressure, V is the volume, m is the mass, R is the specific gas constant for helium, and T is the temperature in Kelvin.
Firstly, we convert the initial temperature from Celsius to Kelvin (50°C + 273.15 = 323.15 K). Then we calculate the mass (m) of the helium using the initial conditions:
m = PV / RT = (2 bar * 2 m3) / (R * 323.15 K)
Note that 1 bar equals 100,000 Pa, and helium's specific gas constant (R) is 2077 J/(kg·K). This gives us the mass of helium.
To determine the heat transfer, we start by finding the final temperature using the combined gas law for the constant volume process:
P1/T1 = P2/T2 -> T2 = P2 * T1 / P1
Once T2 is found, the change in internal energy (ΔU) of the gas can be calculated using ΔU = mCvΔT, where Cv is the specific heat capacity at constant volume for helium (3/2 R per mole). The heat transfer (Q) is equal to ΔU since we are assuming no work done in a constant volume process (W=0).
The correct option regarding the changes in temperature and pressure of an ideal gas in a constant volume process is Option D: the ratio of final/initial temperature equals the ratio of initial/final pressure.