Question

A 3.8 kg block of wood sits on a frictionless table. A 3.0 g bullet, fired horizontally at a speed of 410 m/s, goes completely through the block, emerging at a speed of 220 m/s.

Answer 1

The subject of this question is Physics. The question involves the collision between a bullet and a block of wood, and the calculation of the bullet's initial and final velocities.

Step-by-step explanation:

The subject of this question is Physics. The question involves the collision between a bullet and a block of wood, and the calculation of the bullet's initial and final velocities.

To solve this problem, we can use the principle of conservation of momentum. The momentum before the collision is equal to the momentum after the collision.

Since the block is at rest initially, its momentum is zero.

The momentum of the bullet before the collision is given by its mass (3.0 g) times its initial velocity (410 m/s), and the momentum of the bullet after the collision is given by the same mass times its final velocity (220 m/s). Setting these two expressions equal to each other and solving for the final velocity, we can find that the final velocity of the bullet is 220 m/s.