Final answer:
The neutral molecule C₃H₄F₂ has a total of 30 valence electrons. This is calculated by adding together the valence electrons of each atom: Carbon (12), Hydrogen (4), and Fluorine (14).
Step-by-step explanation:
To find the number of valence electrons in a neutral molecule of C₃H₄F₂, we need to add up the valence electrons of each atom within the molecule. Carbon (C) has 4 valence electrons, Hydrogen (H) has 1 valence electron, and Fluorine (F) has 7 valence electrons.
For the three Carbon atoms:
3 C x 4 valence electrons/C = 12 valence electrons
For the four Hydrogen atoms:
4 H x 1 valence electron/H = 4 valence electrons
For the two Fluorine atoms:
2 F x 7 valence electrons/F = 14 valence electrons
Adding these together gives us:
12 (C) + 4 (H) + 14 (F) = 30 valence electrons in the C₃H₄F₂ molecule.