Answer:
After next 24 hours, bacterial population would be
![1433](https://img.qammunity.org/2022/formulas/mathematics/college/nuon1vrgehgvtwv38ts8ucpeapx3kgxpa8.png)
Explanation:
The initial bacterial count at time = 0 was
At
hours, the bacterial count increased up to
![305](https://img.qammunity.org/2022/formulas/mathematics/college/rx851sz9g5ezmmqn0zefak21ma843q83gi.png)
At
hours, the bacterial count increased up to
![897](https://img.qammunity.org/2022/formulas/mathematics/college/i6gqb0xal0xqsvku14v6licie9tjwzrsiy.png)
As we know that
![P = P_0 * e^(rt)](https://img.qammunity.org/2022/formulas/mathematics/college/ffrx6mwgk4m1jnloy4wlug1cmehqmir0jr.png)
The growth rate of bacterial population is equal to
![r = (log(P)/(P_0) )/(t)](https://img.qammunity.org/2022/formulas/mathematics/college/hefxm56jw5t4jf9edtp3mrfz33hubgbakl.png)
Substituting the above values we get -
![r = (log(897)/(305) )/(24)\\r = 0. 0195](https://img.qammunity.org/2022/formulas/mathematics/college/ocng5su319cnthbc7p9exouv7tlawqzf5w.png)
Count of bacteria after next 24 hours
![P = 897 * e^{ 0.0195 * 24)\\P = 1433](https://img.qammunity.org/2022/formulas/mathematics/college/lgxc69njs2ewzfzlnxzjileu9v61rzclv2.png)