Question

The CERN particle accelerator is circular with a circumference of 7.0 km. (Enter the magnitudes.) (a) What is the acceleration (in m/s²) of the protons?

a) (2.55 X 10^7 m/s^2)
b) (1.27 X 10^7 m/s^2)
c) (3.82 X 10^7 m/s^2)
d) (6.41 X 10^7 m/s^2)

Answer 1

The acceleration of the protons in the CERN particle accelerator can be calculated using the formula acceleration = v^2 / r, where v is the velocity and r is the radius of the circular path. In this case, the circumference of the accelerator is given as 7.0 km, which means the radius is half of the circumference or 3.5 km. However, none of the given options is correct.

Step-by-step explanation:

The acceleration of the protons in the CERN particle accelerator can be calculated using the formula acceleration = v^2 / r, where v is the velocity and r is the radius of the circular path. In this case, the circumference of the accelerator is given as 7.0 km, which means the radius is half of the circumference or 3.5 km. Converting the radius to meters, we get 3.5 km = 3,500 m. Given the options, none of the given values is correct. Please recheck your options or provide more information to determine the correct value.