Question

Calculate the concentration of all ions present in each of the following solutions of strong electrolytes. (a) 0.250 mol of Ca(NO₃)₂ in 100.0 ml of solution.

a) Ca²⁺ = 0.500 M, NO₃⁻ = 1.000 M
b) Ca²⁺ = 0.250 M, NO₃⁻ = 0.250 M
c) Ca²⁺ = 0.125 M, NO₃⁻ = 0.250 M
d) Ca²⁺ = 0.250 M, NO₃⁻ = 0.500 M

Answer 1

The concentration of Ca²⁺ in the given solution is 0.500 M, while the concentration of NO₃⁻ is 1.000 M.

Step-by-step explanation:

To calculate the concentration of all ions present in a solution of a strong electrolyte, we need to consider the dissociation of the compound into its ions. For the given compound Ca(NO₃)₂, it dissociates into Ca²⁺ and 2 NO₃⁻ ions. The concentration of Ca²⁺ is always half the moles of the compound, so for 0.250 mol of Ca(NO₃)₂ in a 100.0 ml solution, the concentration of Ca²⁺ is 0.500 M and the concentration of NO₃⁻ is 1.000 M.