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A 23.2 g piece of space debris is traveling at 81.9 m/s. What is the kinetic energy of the space debris?

a) 77.8 J
b) 0.950 J
c) 145 J
d) 1450 J

User IgKh
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1 Answer

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Final answer:

The kinetic energy of a 23.2 g piece of space debris traveling at 81.9 m/s is calculated using the formula KE = (1/2)mv², resulting in a kinetic energy of 77.8 J.

Step-by-step explanation:

The kinetic energy of an object can be calculated using the formula KE = (1/2)mv², where KE is the kinetic energy, m is the mass of the object, and v is the velocity of the object.

To find the kinetic energy of a 23.2 g piece of space debris traveling at 81.9 m/s, first convert the mass from grams to kilograms (since the standard unit for mass in this equation is kilograms):

23.2 g = 0.0232 kg

Now, plug the values into the formula:

KE = (1/2)mv²

KE = (1/2)(0.0232 kg)(81.9 m/s)²
= (0.5)(0.0232 kg)(6704.61 m²/s²)
= (0.5)(0.0232 kg)(6704.61 J/kg)
= 77.8 J

Therefore, the correct answer is (a) 77.8 J.

User Modig
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