Question

Read and trace through the following Java source code. What best describes the value of x immediately after the following code is executed? int x = 5;

x += 10;
x *= 2;
a. 15
b. 30
c. 20
d. 25

Answer 1

The value of x immediately after the code is executed is 30.

The value of x immediately after the code is executed can be determined by following the steps in the given code.

1. Initialize x to the value 5.
2. Add 10 to the current value of x, resulting in x becoming 15.
3. Multiply the current value of x by 2, resulting in x becoming 30.

Therefore, the value of x immediately after the code is executed is 30.