Final answer:
The force of buoyancy on a 50 cm³ body immersed in water is found using Archimedes' principle. It is equal to the weight of the water displaced by the body. The calculated buoyant force is 0.49 Newtons.
Step-by-step explanation:
To find the force of buoyancy on a body immersed in water, we can use Archimedes' principle. This principle states that the buoyant force on an object submerged in a fluid is equal to the weight of the fluid that the object displaces. Given that the body has a volume of 50 cm³, we must first convert this volume to cubic meters (m³), since the standard unit of volume in the International System of Units (SI) is cubic meters. 1 cm³ is equal to 1×10⁻⁶ m³, so 50 cm³ is 50×10⁻⁶ m³ or 5×10⁻⁵ m³.
The density of water is typically 1000 kg/m³, and the acceleration due to gravity is approximately 9.8 m/s². Using the formula for the mass of the water displaced (mass = density × volume), we get:
Mass of water displaced = 1000 kg/m³ × 5×10⁻⁵ m³ = 0.05 kg.
Now, applying the formula for weight (weight = mass × gravitational acceleration), we find:
Buoyant force = 0.05 kg × 9.8 m/s² = 0.49 N.
Therefore, the buoyant force on the body immersed in water is 0.49 Newtons.