55.5k views
4 votes
Write a function `factors(n)` which accepts a number (n) and returns a list containing all of the factors of that number.

a) *Bold: No specific formatting required.*
b) def factors(n):
c) (textfunction factors(n))
d) def factors(n)

1 Answer

4 votes

Final answer:

The function `factors(n)` can be used to find all the factors of a given number (n).

Step-by-step explanation:

The function `factors(n)` can be used to find all the factors of a given number (n).

The factors of a number are the numbers that divide evenly into it without leaving a remainder.

To find the factors, we can use a for loop that checks each number from 1 to n and checks if it divides evenly into n.

If it does, we add it to a list of factors. Here is an example implementation:

def factors(n):
factor_list = []
for i in range(1, n + 1):
if n % i == 0:
factor_list.append(i)
return factor_list

print(factors(12))
# Output: [1, 2, 3, 4, 6, 12]

User Jakob Buron
by
8.9k points