Final answer:
The statement that the relationship between displacement 'd' and time 't' for an object with constant acceleration 'a' is given by the equation d = (1/2)at^2 is true, confirming that displacement grows with the square of time for constant acceleration.
Step-by-step explanation:
The statement given in the question 'When an object is subjected to a constant acceleration 'a', the relationship between distance 'd' and time 't' is given by d= (1/2)at^2' is True. This is a basic concept in kinematics, a part of physics that deals with the motion of objects without considering the forces that cause the motion. The correct equation of motion for an object under constant acceleration is d = (1/2)at^2, where 'd' is the displacement, 'a' is the acceleration, and 't' is the time elapsed. Additionally, this equation indicates that the displacement of an object is directly proportional to the square of the time, which means that the graph of displacement versus time squared (t^2) will indeed be a straight line, affirming that a graph of displacement versus time (t) yields a parabolic curve.