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What is the empirical forμla of a compound composed of 25.3 g of potassium (K) and 5.18 g of oxygen (O)? Insert subscripts as needed.

a) K2O
b) KO
c) K2O_2
d) KO_2

User Ron Klein
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Final answer:

The empirical formula of a compound composed of 25.3 g of potassium and 5.18 g of oxygen is K2O. This is determined by converting the masses to moles, then finding the simplest whole number ratio, which in this case is 2:1 for K:O.

Step-by-step explanation:

To determine the empirical formula of a compound composed of potassium (K) and oxygen (O), we need to convert the given masses to moles. The molar mass of potassium is 39.10 g/mol and the molar mass of oxygen is 16.00 g/mol. We then use these values to calculate the number of moles:
Moles of K = 25.3 g / 39.10 g/mol ≈ 0.647 moles
Moles of O = 5.18 g / 16.00 g/mol ≈ 0.324 moles. The next step is to divide each by the smallest number of moles to get the ratio of the elements:
Ratio of K:O = 0.647:0.324 ≈ 2:1.
Therefore, the empirical formula of the compound is K2O, which corresponds to option (a) K2O.

User Jstine
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