Final answer:
Structures for 5-bromo-3-iodoheptanal and 5-bromo-4-ethyl-2-heptanone involve drawing a heptane backbone and adding the respective substituents: an aldehyde functional group, bromine, iodine for the first, and a ketone functional group, bromine and an ethyl group for the second.
Step-by-step explanation:
The task is to draw the structure for each specified compound. Let's break down the instruction for each one:
- 5-bromo-3-iodoheptanal: This is a seven-carbon chain (heptanal indicating an aldehyde with seven carbons). The functional group, an aldehyde, is on the first carbon. A bromine (Br) is attached to the fifth carbon, and an iodine (I) to the third carbon.
- 5-bromo-4-ethyl-2-heptanone: Again, this is a seven-carbon chain, with a ketone functional group on the second carbon. There is a bromine on the fifth carbon and an ethyl group on the fourth carbon.
The carbon backbone for each of these molecules is a heptane chain, and the substituents are added as per the numbering in the names given above, with a carbonyl group for the aldehyde and ketone respectively.