Question

if the 50 kg crate is subjected to a force of p=200n and the coefficient of kinetic friction between the create and ground is µk= 0.3, determine is speed when it has traveled 15m starting from rest and the total work done ?

Answer 1

The speed of the crate after traveling 15m starting from rest is determined to be 5205 J and the total work done is 5205 J.

Step-by-step explanation:

To determine the speed of the crate after traveling 15m starting from rest, we need to calculate the work done by the applied force and the work done by friction. First, let's calculate the work done by the applied force:

Work done by applied force:

Work = Force x Distance

W = P x d

W = 200 N x 15 m = 3000 J

Next, let's calculate the work done by friction:

Work done by friction:

Work = Force of friction x Distance

W = (µk x Normal force) x d

Normal force = mass x gravity

Normal force = 50 kg x 9.8 m/s^2 = 490 N

W = (0.3 x 490 N) x 15 m = 2205 J

The total work done is the sum of the work done by the applied force and the work done by friction:

Total work done = 3000 J + 2205 J = 5205 J

Therefore, the speed of the crate after traveling 15m starting from rest is determined to be 5205 J and the total work done is 5205 J.