Question

The angle where 2.4 rad/s². Determine the magnitude of the acceleration at 3 s. Round the result to one decimal place.

a) 7.2 m/s²
b) 5.6 m/s²
c) 9.8 m/s²
d) 3.5 m/s²

Answer 1

The magnitude of the acceleration at 3 seconds for an object with an angular acceleration of 2.4 rad/s² is found by multiplying the angular acceleration by the time interval, giving a result of 7.2 m/s².

Step-by-step explanation:

To determine the magnitude of the acceleration at 3 seconds for an object with an angular acceleration of 2.4 rad/s², we use the formula for angular acceleration, α = Δω / Δt, where Δω is the change in angular velocity and Δt is the change in time. Since we are given that the angular acceleration is 2.4 rad/s², to find the change in velocity at 3 s, we multiply the angular acceleration by the time interval.

The change in angular velocity after 3 s is Δω = α × t = 2.4 rad/s² × 3 s = 7.2 rad/s. Therefore, the answer is option (a) 7.2 m/s², assuming that the angular acceleration is directly proportional to the linear acceleration, which is the case when the radius is constant and equal to 1 meter.