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The Atwood machine - two masses hanging from a rope that is draped over a pulley. Consider the variant where the whole machine is suspended from a spring. We will write the masses, ( m_1 ) and ( m_2 ), as a fraction of the total mass ( m ) where ( m_1 ).

a. ( m_1 + m_2 )
b. ( m_1m + m_2m )
c. ( m_1m - m_2m )
d. ( m_1 ⋅ m_2m )

User SudarP
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1 Answer

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Final answer:

The fraction that represents the masses (m1) and (m2) in an Atwood machine in terms of the total mass (m) is (m1/m) and (m2/m) respectively. The closest multiple-choice option is (a) & (b)

Step-by-step explanation:

The expression that represents the masses (m) a1nd (m2) in terms of the total mass (m) in an Atwood machine is (a) (m1/m) and (b) (m2/m).

For example, if the total mass is 10 kg and m1 is 2 kg, then the fraction would be (2/10) or 0.2.

The closest multiple-choice option is (a) & (b)

User Little Bird
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