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A 2.41 kg ball is attached to a ceiling by a 0.749 m long string. The height of the room is 3.37 m. The acceleration of gravity is 9.81 m/s^2. What is the gravitational potential energy associated with the ball relative to a) the ceiling?

a) X Joules
b) Y Joules
c) Z Joules
d) W Joules

1 Answer

2 votes

Final answer:

The gravitational potential energy associated with the ball relative to the ceiling is 17.78 Joules.

Step-by-step explanation:

The gravitational potential energy associated with the ball relative to the ceiling can be calculated using the formula:

E = mgh

where E is the gravitational potential energy, m is the mass of the ball, g is the acceleration due to gravity, and h is the height of the ball above the reference point, in this case, the ceiling.

Given:

  • Mass of the ball (m) = 2.41 kg
  • Height of the ball above the ceiling (h) = 0.749 m
  • Acceleration due to gravity (g) = 9.81 m/s^2

Plugging in the values:

E = 2.41 kg * 9.81 m/s^2 * 0.749 m = 17.78 Joules

Therefore, the gravitational potential energy associated with the ball relative to the ceiling is 17.78 Joules (option X).

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