Question

I need help with all three questions for this problem

Answer 1

Answer:

Step-by-step explanation:

The given force is:

`F=(2.2N)x+(1.0N)y`

Part A

If the displacement of the dog is:

d = (0.29m)x

The work done is the dot product of the force and displacement

`\begin{gathered} W=F.d \\ \\ W=\text{ \lparen2.2\rparen\lparen0.29\rparen+\lparen1.0\rparen\lparen0\rparen} \\ \\ W=0.638Joules \end{gathered}`

Part B

If the displacement of the dog is:

d = (0.29m)y

The workdone will be calculated as:

`\begin{gathered} W=F.d \\ \\ W=(2.2)(0)+(1.0)(0.29) \\ \\ W=0.29\text{ Joules} \end{gathered}`