Final answer:
When two masses are connected by a rope or string and one is pulling the other, the tension in the rope is the same for both masses. b) 2 m/s².
Step-by-step explanation:
To find the acceleration when a 18 kg mass is pulling a 7 kg mass, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration (F = m * a). In this case, the force is the tension in the rope connecting the two masses.
Let's denote the acceleration as 'a' and set up the equation for each mass:
![\[ F_(18) = m_(18) \cdot a \]](https://img.qammunity.org/2024/formulas/physics/high-school/dh2hcbfasl2dn0qaxg6cujkm6sb00yncm2.png)
![\[ F_(7) = m_(7) \cdot a \]](https://img.qammunity.org/2024/formulas/physics/high-school/dbdmmm6xpytxp348frqsuliw4452kb4ozn.png)
Given that the mass of the first object (18 kg) is pulling the second object (7 kg), we have:
![\[ F_(18) = F_(7) \]](https://img.qammunity.org/2024/formulas/physics/high-school/1k85iq2m80u9gp5vglqb208uaedo3no0h4.png)
Substituting in the known values:
![\[ 18 \cdot a = 7 \cdot a \]](https://img.qammunity.org/2024/formulas/physics/high-school/11guqpqwv9rsrxksovl2s1xd5ibt5c9emq.png)
Solving for 'a', we get:
![\[ a = (7)/(18) \, \text{m/s²} \]](https://img.qammunity.org/2024/formulas/physics/high-school/m9vh8dn9btomxiqk2gd4u41l6mvlz36xmx.png)
Therefore, the correct acceleration is 2 m/s².