Question

Assume we have an integer pointer declared named p1. Which of the following statements correctly prints out the value that is in the memory address that the pointer p1 is pointing to?

A. printf("*p1");
B. printf("p1");
C. printf("&p1");
D. printf("p1");

Answer 1

The correct way to print the value pointed by an integer pointer p1 in C is with the statement A. printf("%d", *p1);, where %d is the format specifier for integers.

Step-by-step explanation:

The question pertains to how to print the value stored at the memory address to which an integer pointer p1 is pointing in the C programming language. Among the options provided, the correct answer is A. printf("%d", *p1);. Here is why the other options are incorrect:

• B. printf("p1"); - This would print the text 'p1', not the value or address.
• C. printf("&p1"); - This would print the address of the pointer variable itself, not the value it's pointing to.
• D. printf("p1"); - Identical to option B, printing the text 'p1'.

To clarify, the asterisk (*) is the dereference operator and *p1 accesses the value at the address stored in the pointer variable p1. The printf function requires a format specifier (%d for integers) to properly print the value.