Answer:
Power supplied to the pump is 980000 W or 980 KW
Note: The question is incomplete. The complete question is given below:
On a day with no wind, a fountain in Switzerland propels 30000 kg of water per minute to a height of 140 metres.
a)Calculate the power used in raising the water?
b)The efficiency of the pump which operates the fountain is 70%
calculate the power supplied to the pump?
Step-by-step explanation:
Efficiency = Power output/Power input * 100%
Power output = work done/ time
where work done = mass * acceleration due to gravity (g) * height
time = 1 minute = 60 seconds
mass of water = 30000 kg, height = 140 meters, g = 9.8 m/s²
Then, work done = 30000 * 140 * 9.8 = 41160000 J
Power output then = 41160000 J / 60 s
Power output = 686000 W
The power input can then be derived from the formula of efficiency
Power input = (Power output * 100)/Efficiency
Power input = (100 * 686000) / 70
Power input = 980000 W
Therefore, power supplied to the pump is 980000 W or 980 KW