Final answer:
The net magnetic field at point P due to the two parallel currents in the wires, given the distances from P to each wire and the current, is 7.5 * 10^-6 T. This is calculated using Ampere's Law for each wire and then finding the difference since they are in the opposite direction. However, this result does not match the provided options.
Step-by-step explanation:
To calculate the magnetic field at point P due to two parallel currents, we use Ampere's Law. The magnetic field due to a long, straight conductor at a distance 'r' from the wire is given by B = (\(\mu_0\) * I) / (2 * \(\pi\) * r), where \(\mu_0\) is the permeability of free space (\(\mu_0\) = 4\(\pi\) * 10-7 T*m/A), and I is the current.
For the top wire with current 1.5 A and Point P at 0.02 m, the magnetic field Btop will be out of the page (using the right-hand rule). Similarly, for the bottom wire with current 1.5 A and Point P at 0.04 m, the magnetic field Bbottom will be into the page.
Calculating for both:
- Btop = (4\(\pi\) * 10-7 T*m/A * 1.5 A) / (2 * \(\pi\) * 0.02 m) = 1.5 * 10-5 T
- Bbottom = (4\(\pi\) * 10-7 T*m/A * 1.5 A) / (2 * \(\pi\) * 0.04 m) = 0.75 * 10-5 T
The net magnetic field at point P would be the difference between the two, since they are in opposite directions:
Bnet = Btop - Bbottom = 1.5 * 10-5 T - 0.75 * 10-5 T = 0.75 * 10-5 T
Therefore, the net magnetic field at point P is 7.5 * 10-6 T, which is not in the answer choices provided by the student and suggests there may be a discrepancy in the question or provided choices.