Question

Starting from 300 feet away, a car drives toward you. It then passes by you at a constant speed of 48 feet per second. The distance d (in feet) of the car from you after t seconds is given by the equation d=300−48t.

a) d decreases linearly with t
b) d increases linearly with t
c) d remains constant with t
d) d is a quadratic function of t

Answer 1

The car's distance from you decreases linearly with time since it is traveling towards you at a constant speed, which is reflected in the linear function d=300-48t with a negative slope.

Step-by-step explanation:

The distance d of the car from you, as described by the equation d=300−48t, decreases linearly with time t. This is because the equation is in the form of a straight line equation y=mx+b, where m is the slope and b is the y-intercept. Since the slope is negative (-48), this indicates that as time increases, the distance decreases. This linear decrease is consistent with the car moving towards you at a constant speed of 48 feet per second. As time passes, the car's position changes with every second, moving it closer to your reference point by 48 feet. Therefore, the correct option is (a) d decreases linearly with t.