56.8k views
3 votes
A 6.0kg block hangs from the celling of an elevator by a massless rope. Another block with 12.0 kg of mass hangs from the first block by another massless rope.

The elevator is speeding up towards the top floor at a rate of 2.00 m/s^2. What is the tension in each rope?
Tension in the first rope
your answer.....
Unit for Tension in the first rope: N
Unit for Tension in the bottom rope: N
Tension in the bottom rope=

1 Answer

5 votes

Step-by-step explanation:

Using F = m a

Tension when not moving =

top rope = (6 + 12 ) kg * 9.81 m/s^2 = 176.58 N

bottom rope 12 * 0.81 = 117.72 N

When accelerated upwards at 2 m/s^2 this adds to the usual acceleration of 9.81 m/s^2

top rope 18 * ( 9.81+2) = 212.58 N

bottom rope = 12 * ( 9.81 +2 ) = 141.72 N

User Will Hawker
by
8.3k points