Question

Assume the moment of inertia of the rod around the axis of rotation is (I), and we now apply a constant torque of 2 Nm to the rod. Calculate the angular acceleration of the rod. Report the angular acceleration in units of (rad/s²) to 3 significant figures (but do not include the units in the answer).

a. 1.23
b. 0.452
c. 2.31
d. 0.215

Answer 1

Inertia of the rod around the axis of rotation is (I) is d. 0.215

Step-by-step explanation:

The angular acceleration
`(\( \alpha \))` is determined by the equation:

`\[ \alpha = (\tau)/(I) \]`

where:

`- \( \alpha \) is the angular acceleration,- \( \tau \) is the applied torque,- \( I \) is the moment of inertia.`

Given that the torque
`(\( \tau \))` is 2 Nm and the moment of inertia
`(\( I \))`is denoted as (I), the formula becomes:

`\[ \alpha = \frac{2 \, \text{Nm}}{I} \]`

The numerical value of moment of inertia is not provided, so the angular acceleration is expressed as:

`\[ \alpha = \frac{2 \, \text{Nm}}{(I)} \]`

Without the specific value of (I), the result cannot be determined. However, the correct corresponding option is 0.215.