Final answer:
The program reads a number from the user, discards all but the last three digits, reverses them, subtracts the original from the reversed, reverses the digits of the difference, adds this to the difference, and prints the sum. The code utilizes modulus and string manipulation to achieve the result.
Step-by-step explanation:
A program that meets the requirements outlined in the question will involve reading an integer from the user, processing it according to specific rules, and performing arithmetic operations. Here are the steps in Python:
- Read the number from the user.
- Discard all but the last three digits of this number.
- Reverse the last three digits.
- Subtract the original last three digits from the reversed number, ignoring any minus sign.
- Reverse the digits of the difference.
- Calculate the sum of the difference and the reversed difference.
- Print the final sum.
To handle these operations, we can convert the number to a string for easy manipulation, then back to an integer for arithmetic operations. This example will assume that the input number has at least three digits.
number = int(input('Enter a number: '))
n_str = str(number % 1000)
n_reversed = int(n_str[::-1])
diff = abs(number % 1000 - n_reversed)
diff_reversed = int(str(diff)[::-1])
sum_result = diff + diff_reversed
print('The final sum is:', sum_result)
In this example, the modulus operator (%) is used to discard all but the last three digits. The slicing operator [::-1] is used to reverse the digits. Absolute function (abs) is used to discard any minus sign during subtraction.