Final answer:
To draw a circuit diagram of two resistors in parallel connected in series with a third resistor, we can start by drawing the two resistors in parallel and then connecting the third resistor in series. The equivalent resistance can be calculated using the formula 1/Req = 1/R1 + 1/R2 + 1/R3, where R1, R2, and R3 are the resistances of the individual resistors. The current flowing through each resistor can be calculated using Ohm's law, and the voltage drop across each resistor can also be calculated using Ohm's law.
Step-by-step explanation:
To draw a circuit diagram of two resistors in parallel connected in series with a third resistor, we can start by drawing the two resistors in parallel. This means that one end of both resistors is connected together, and the other end of both resistors is also connected together. Then, we can draw the third resistor connected in series with the parallel combination. This means that one end of the third resistor is connected to the end of one of the resistors in parallel, and the other end of the third resistor is connected to the end of the other resistor in parallel.
To calculate the equivalent resistance, we can use the formula:
1/Req = 1/R1 + 1/R2 + 1/R3
where R1, R2, and R3 are the resistances of the individual resistors. In this case, R1 and R2 are both 10 ohms, and R3 is 5 ohms. Plugging these values into the formula, we get:
1/Req = 1/10 + 1/10 + 1/5
Simplifying the equation, we find that:
1/Req = 1/5
Therefore, the equivalent resistance (Req) is 5 ohms.
To calculate the current flowing through each resistor, we can use Ohm's law: I = V/R, where I is the current, V is the voltage, and R is the resistance. Since the resistors are connected in series, the current through each resistor will be the same. Using a 12 volt battery, we can calculate the current:
I = V/R = 12/5 = 2.4 amps
Therefore, the current flowing through each resistor is 2.4 amps.
To calculate the voltage drop across each resistor, we can use Ohm's law again. Since the current through each resistor is the same (2.4 amps), we can calculate the voltage drop:
V = I*R
For the resistors in parallel, the voltage drop across each resistor will be the same:
V1 = 2.4 * 10 = 24 volts
V2 = 2.4 * 10 = 24 volts
For the third resistor, the voltage drop will be:
V3 = 2.4 * 5 = 12 volts