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an insulating sphere of radius is charged unevenly. the volume charge density as a function of radial distance from the center is () = 0 . (a) what is the total charge of the sphere?

User Xrabbit
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Final answer:

To find the total charge of the insulating sphere, integrate the charge density function over the volume of the sphere using the given formula λ(r) = ar^2. The total charge is Q = a * 4π/5 * R^5.

Step-by-step explanation:

To find the total charge of the insulating sphere, we need to integrate the charge density function over the volume of the sphere. Given that the charge density as a function of radial distance from the center is λ(r) = ar^2, where a is a constant, we can set up the integral as follows:

Q = ∫ λ(r) dV

Since the sphere is insulating, the charge is distributed throughout its volume, so the integral becomes:

Q = ∫ a*r^2 dV

We can solve this integral by considering the volume element dV = 4πr^2 dr, where dr is an infinitesimal shell of thickness dr. Substituting these values, we get:

Q = ∫ a*r^2 * 4πr^2 dr

Integrating over the limits of the radius from 0 to R, where R is the radius of the sphere, we obtain the total charge of the sphere:

Q = a * 4π * ∫[0]^R r^4 dr = a * 4π/5 * R^5

Therefore, the total charge of the sphere is Q = a * 4π/5 * R^5.

User Hydeph
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