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Find how many pounds of BOD enter a plant each day in the daily plant flow is 2 MGD with a BOD concentration of 200 mg/L.

User Xfeep
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Final answer:

The plant receives 3,337.81 pounds of biochemical oxygen demand (BOD) each day, calculated by converting 2 MGD of flow to liters and then converting the BOD concentration from mg/L to pounds.

Step-by-step explanation:

To find the number of pounds of biochemical oxygen demand (BOD) that enter a plant each day, we need to perform unit conversions and calculations using the given flow rate and BOD concentration.

The daily plant flow is 2 million gallons per day (MGD), and the BOD concentration is 200 milligrams per liter (mg/L).

First, we convert the flow rate from gallons to liters:

  • 1 gallon = 3.78541 liters
  • 2 million gallons/day × 3.78541 liters/gallon = 7.57082 million liters/day

Next, we convert the mass of BOD from mg to pounds:

  • 1 pound = 453,592 mg
  • 200 mg/L × 7.57082 million liters = 1.514164 × 109 mg/day
  • 1.514164 × 109 mg/day ÷ 453,592 mg/pound = 3337.81 pounds/day

Therefore, 3,337.81 pounds of BOD enter the plant each day.

User Ojek
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