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14 votes
14 votes
X^2 +2= 0I need help with solving this quadratic equation.

User Sam Kington
by
2.2k points

1 Answer

25 votes
25 votes
Answer:
x\text{ = }-i\sqrt[]{2}\text{ or i}\sqrt[]{2}Step-by-step explanation:

The given quadratic equation is:


x^2+2=0

Subtract 2 from both sides


\begin{gathered} x^2+2-2=0-2 \\ x^2=\text{ -2} \end{gathered}

Find the square root of both sides


\begin{gathered} \sqrt[]{x^2}=\text{ }\sqrt[]{-2} \\ x=\sqrt[]{-2} \\ x=\pm\sqrt[]{2}*\sqrt[]{-1} \\ x\text{ =}\pm\text{ }\sqrt[]{2}i \\ x\text{ = }\pm i\sqrt[]{2} \end{gathered}
\begin{gathered} x\text{ = }-i\sqrt[]{2}\text{ or i}\sqrt[]{2} \\ \end{gathered}

User Steven Johnston
by
2.5k points
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