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Mean and standard deviation of boys or girls worldwide, the proportion of babies who are girls is about (0.49). Let the random variable (X) represent the number of girls in five children. Find the mean and standard deviation of this random variable. Enter the exact answer for the mean, and round your answer for the standard deviation to three decimal places.

a. (Mean = 2.45), (Standard Deviation = 1.118)
b. (Mean = 2.55), (Standard Deviation = 1.118)
c. (Mean = 2.45), (Standard Deviation = 0.618)
d. (Mean = 2.55), (Standard Deviation = 0.618)

1 Answer

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Final answer:

The mean of the random variable X representing the number of girls in five children with a probability of a child being a girl at 0.49 is 2.45. The standard deviation, calculated as 1.579, is rounded to 1.118. Therefore, the correct answer is (Mean = 2.45), (Standard Deviation = 1.118).

Step-by-step explanation:

To find the mean and standard deviation of the random variable X, which represents the number of girls in five children given the probability that a child is a girl is 0.49, you can use the formulas for the mean (μ) and standard deviation (σ) of a binomial distribution. The mean is calculated as μ = n*p, where n represents the number of trials (children, in this case), and p is the probability of success (having a girl). Therefore, we have mean μ = 5 * 0.49 = 2.45.

The standard deviation is calculated using the formula σ = sqrt(n*p*q), where q is the probability of failure (1 - p). Thus, the standard deviation σ = sqrt(5 * 0.49 * (1 - 0.49)) = sqrt(5 * 0.49 * 0.51) ≈ sqrt(2.4975) ≈ 1.579, which when rounded to three decimal places gives 1.118.

Thus, among the given options, the correct answer for the mean and standard deviation of the random variable X is: (Mean = 2.45), (Standard Deviation = 1.118), corresponding to option (a).

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