Question

Solve the following problem using the 4-step plan. Use th concept of GCF or LCM in each problem. Write your answer in your notebook. 1)There are always 4 bars of chocolates left when box of chocolate share equally among 8, 10 or 12 children. Find the smallest number of chocolates the box?

Answer 1

Using the Least Common Multiple (LCM) of 8, 10, and 12, which is 120, and adding the remainder of 4 chocolates, the smallest number of chocolates in the box is 124.

Step-by-step explanation:

To solve the initial problem, we need to find the smallest number of chocolates that when divided by 8, 10, or 12 children, always leaves 4 bars of chocolates. This problem involves finding the Least Common Multiple (LCM) of the divisors 8, 10, and 12, and then adding the remainder, which is 4, to it.

1. Find the LCM of 8, 10, and 12 which is 120.
2. Add the remainder to the LCM: 120 + 4 = 124.

Therefore, the smallest number of chocolates in the box is 124.