Question

A simple pendulum undergoes one complete oscillation in 5.42 s. Find the frequency and the angular frequency of the oscillation. (a) Frequency Hz (b) Angular frequency rad/s

a) Frequency: 0.184 Hz, Angular frequency: 1.16 rad/s
b) Frequency: 5.42 Hz, Angular frequency: 34.08 rad/s
c) Frequency: 0.184 Hz, Angular frequency: 34.08 rad/s
d) Frequency: 5.42 Hz, Angular frequency: 1.16 rad/s

Answer 1

The frequency of a simple pendulum completing one oscillation in 5.42 s is 0.184 Hz, and its angular frequency is 1.16 rad/s, making option (a) the correct answer.

Step-by-step explanation:

The question pertains to the frequency and angular frequency of a simple pendulum oscillation. A simple pendulum undergoing one complete oscillation in 5.42 seconds has a frequency, which is the reciprocal of the period. Thus, the frequency (f) is calculated as:

f = 1 / T = 1 / 5.42 s = 0.184 Hz

The angular frequency (ω), related to the frequency, is given by the formula:

ω = 2πf = 2π(0.184 Hz) ≈ 1.16 rad/s

Therefore, the correct answer is:

• (a) Frequency: 0.184 Hz, Angular frequency: 1.16 rad/s