Final answer:
Option b is the only dimensionally correct expression for the length scale (l) since it yields a dimension of length (L), making it consistent with the base quantities and their dimensions.
Step-by-step explanation:
To determine which expression(s) for the length scale (l) is dimensionally correct, it is essential to remember that the dimension of any physical quantity can be expressed as a product of powers representing the base quantities. The provided variables have the following dimensions in the International System of Units (SI):
- Permittivity (ε): M-1L-3T4I2
- Boltzmann constant (kB): M1L2T-2Θ-1
- Absolute temperature (T): Θ
- Number per unit volume (n): L-3
- Charge (q): I1T1
The correct expression for l must yield dimensions of length (L1). Let's assess the given options:
- a. l = √(nq2/εkBT) = √(L-3(IT)2/(M-1L-3T4I2ML2T-2Θ-1)) = √(M0L1T0I0Θ0) = L1/2
- b. l = √(εkBT/nq2) = √(M-1L-3T4I2ML2T-2Θ-1/L-3(IT)2) = √(M0L1T0I0Θ0) = L1/2
- c. l = √(q2εn2/3kBT) does not yield a dimension of length and is incorrect.
- d. l = √(q2εn1/3kBT) does not yield a dimension of length and is incorrect.
Therefore, option b. is the only dimensionally correct expression for the length scale l.