Final answer:
There are 10 different strings that can be formed using 2 zeros and 3 ones, calculated by using the permutations of a multiset formula.
Step-by-step explanation:
To determine how many strings can be formed using 2 zeros ('0') and 3 ones ('1'), you must consider all possible arrangements of these numbers. This is a combinatorial problem that can be solved using the concept of permutations of multisets. Since we have a total of 5 positions to fill and 2 kinds of digits (zeros and ones), with repetition of digits allowed, we can use the formula for permutations of a multiset which is n!/(n1! * n2! * ... * nk!), where n is the total number of items, n1 is the number of items of type 1, and so on.
For our specific case with 2 zeros and 3 ones, that would be 5!/(2! * 3!) = (5 * 4 * 3 * 2 * 1)/(2 * 1 * 3 * 2 * 1) = 5 * 4 / 2 = 10. Therefore, there are 10 different strings that can be formed with 2 zeros and 3 ones.