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A metallic rectangular block measures 2.00 cm by 3.00 cm by 4.50 cm. If its density is 11.34 g/cm?, what is the mass of this metallic rectangular block? (Hint: D = m/] A. 0.420 g B. 15.7 g C. 27.0 g D.​306 g

User Jimmery
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Final answer:

The mass of a metallic block with dimensions 2.00 cm by 3.00 cm by 4.50 cm and a density of 11.34 g/cm³ is calculated by finding the volume and then using the formula m = D × V. The calculated mass is 306 g.

Step-by-step explanation:

The student asked about determining the mass of a metallic rectangular block with known dimensions and density. To find the mass of the metallic block, we need to first calculate the volume by multiplying the dimensions (length × width × height) and then multiply this volume by the block's density.

The formula for density is D = m/V, meaning density equals mass divided by volume. Given this block's density of 11.34 g/cm³, we can rearrange the formula to m = D × V to find the mass.

First, we calculate the block's volume: Volume = 2.00 cm × 3.00 cm × 4.50 cm = 27.00 cm³. Then we use the density to find the mass: Mass = 11.34 g/cm³ × 27.00 cm³ = 306 g.

Therefore, the mass of the metallic rectangular block is 306 g, which corresponds to option D.

User Kitwradr
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