Final answer:
To find where the instantaneous rate of change equals the average rate of change, calculate the derivative of a function to get the instantaneous rate, compare it to the average rate, and solve for the point where they are equal. This is typically done in calculus and is simplified if acceleration is constant.
Step-by-step explanation:
The question is about finding where the instantaneous rate of change is equal to the average rate of change. This is a common problem in calculus involving differential equations. To solve for a moment where these rates are equal, you would normally calculate the derivative of a function to find the instantaneous rate of change and compare it to the average rate of change over a given interval. If we assume that acceleration is constant, as mentioned in the provided context, then the calculation simplifies since the average and instantaneous accelerations are the same. However, typically, you would set the derivative equal to the average rate of change and solve for the specific point (x-value) where they align. Graphically, this can be visualized on a plot where the slope of the tangent line (representing the instantaneous rate of change) at a specific point is equal to the slope of the secant line (representing the average rate of change) over an interval.