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What is the vertices of (-5, 2) and (-5, -3) and (-10, -3) and (-10, 2) in perimeter units?

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Final answer:

The perimeter of the shape with the given vertices is 20 units, calculated by adding the lengths of the horizontal and vertical sides.

Step-by-step explanation:

To find the perimeter of the shape with vertices at (-5, 2), (-5, -3), (-10, -3), and (-10, 2), we need to calculate the distances between adjacent vertices. Since these points form a rectangle with sides parallel to the x and y axes, we can simply use the difference in x-coordinates (for horizontal sides) and y-coordinates (for vertical sides) to find the lengths of the sides.

The horizontal sides are between (-5, 2) and (-10, 2), and (-5, -3) and (-10, -3), each having a length of |-5 - (-10)| = |5| = 5 units. The vertical sides are between (-5, 2) and (-5, -3), and (-10, 2) and (-10, -3), each having a length of |2 - (-3)| = |5| = 5 units. Therefore, the perimeter is 2*(length of horizontal side) + 2*(length of vertical side) = 2*5 + 2*5 = 20 units.

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