Final answer:
The solution with 0.059M MgBr2 has the greatest concentration of Br- ions at 0.118M since each molecule of MgBr2 yields two bromide ions.
Step-by-step explanation:
To determine which of the solutions has the greatest concentration of Br- ions, let's examine each one:
- a. 0.110M KBr: Each mole of KBr yields one mole of Br- ions, so the concentration of Br- ions will be the same as the given concentration, which is 0.110M.
- b. 0.075M NH4Br: Similar to KBr, each mole of NH4Br yields one mole of Br- ions. Thus, the concentration of Br- is also 0.075M.
- c. 0.059M MgBr2: Each mole of MgBr2 yields two moles of Br- ions. Therefore, the concentration of Br- ions will be twice the given concentration, which is 0.059M * 2 = 0.118M.
- d. 0.035M FeBr3: Each mole of FeBr3 yields three moles of Br- ions. Thus, the concentration of Br- ions will be three times the given concentration, which is 0.035M * 3 = 0.105M.
Comparing the concentrations of Br- ions produced by each solution, 0.059M MgBr2 produces the highest number of bromide ions because of the multiplier effect of having two bromides per formula unit of MgBr2.