Final answer:
In summary, the sum of all alternating sums for the set (A = 1, 2, 3) is 0. This is because the alternating subtraction and addition of the numbers in the subsets cancel each other out.
Step-by-step explanation:
The question asks to find the sum of all alternating sums for the set (A = 1, 2, 3). The alternating sum for a subset is defined by arranging the numbers in the subset in decreasing order and then subtracting and adding them alternatively, starting with the largest number. We can list all the non-empty subsets of A and their respective alternating sums as follows:
- For subset {3}: The alternating sum is 3.
- For subset {2}: The alternating sum is 2.
- For subset {1}: The alternating sum is 1.
- For subset {3,2}: The alternating sum is 3 - 2 = 1.
- For subset {3,1}: The alternating sum is 3 - 1 = 2.
- For subset {2,1}: The alternating sum is 2 - 1 = 1.
- For subset {3,2,1}: The alternating sum is 3 - 2 + 1 = 2.
To find the sum of all such alternating sums, we add them together: 3 + 2 + 1 + 1 + 2 + 1 + 2 = 12. However, since each number 1, 2, and 3 appears in exactly half of the subsets (both alone and in pairs), their contributions cancel out when the subtraction aspect of the alternating sums is considered, resulting in an overall sum of 0.