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1. A motor car of mass 1000 kg is travelling round a circular track with a velocity of 15 m/s. if the radius of the track is 400 m, find the horizontal thrust exerted on the wheels.?

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Final answer:

The horizontal thrust exerted on the wheels of a 1000 kg car traveling at 15 m/s around a 400 m radius circular track is 562.5 Newtons. This thrust is the centripetal force required to maintain the car's circular motion.

Step-by-step explanation:

Finding the Horizontal Thrust on Car Wheels in Uniform Circular Motion

To find the horizontal thrust exerted on the wheels of a car travelling around a circular track, we can use the concept of centripetal force, which is the force required to keep an object moving in a circular path. The formula for centripetal force (Fc) is:

Fc = (m × v2) / r, where:

  • m is the mass of the object (in this case, the car)
  • v is the velocity of the object
  • r is the radius of the circular path

Plugging in the values from the question, we get:

Fc = (1000 kg × (15 m/s)2) / 400 m

Fc = (1000 × 225) / 400

Fc = 225000 / 400

Fc = 562.5 N

Therefore, the horizontal thrust exerted on the wheels is 562.5 Newtons.

Note that this horizontal thrust is equivalent to the centripetal force necessary to keep the car moving in a circle at the given speed and radius.

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